The winning Connecticut Play3 numbers for March 17, 2002 were: night 1-6-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 17, 2002 | Night | 1-6-2 | 9 | 9 |
| Mar 16, 2002 | Night | 0-2-3 | 5 | 5 |
| Mar 15, 2002 | Night | 7-1-9 | 17 | 8 |
| Mar 15, 2002 | Day | 4-3-0 | 7 | 7 |
| Mar 14, 2002 | Night | 2-0-0 | 2 | 2 |
| Mar 14, 2002 | Day | 2-7-1 | 10 | 1 |
| Mar 13, 2002 | Night | 9-1-8 | 18 | 9 |
| Mar 13, 2002 | Day | 4-3-0 | 7 | 7 |
| Mar 12, 2002 | Night | 8-3-6 | 17 | 8 |
| Mar 12, 2002 | Day | 1-5-0 | 6 | 6 |
| Mar 11, 2002 | Night | 2-3-7 | 12 | 3 |
| Mar 11, 2002 | Day | 8-2-9 | 19 | 1 |