The winning Connecticut Play3 numbers for March 9, 2002 were: night 8-4-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 9, 2002 | Night | 8-4-9 | 21 | 3 |
| Mar 8, 2002 | Night | 8-0-0 | 8 | 8 |
| Mar 8, 2002 | Day | 1-9-1 | 11 | 2 |
| Mar 7, 2002 | Night | 1-9-3 | 13 | 4 |
| Mar 7, 2002 | Day | 2-2-1 | 5 | 5 |
| Mar 6, 2002 | Night | 3-1-8 | 12 | 3 |
| Mar 6, 2002 | Day | 6-1-8 | 15 | 6 |
| Mar 5, 2002 | Night | 6-8-6 | 20 | 2 |
| Mar 5, 2002 | Day | 5-1-9 | 15 | 6 |
| Mar 4, 2002 | Night | 5-6-1 | 12 | 3 |
| Mar 4, 2002 | Day | 7-6-7 | 20 | 2 |
| Mar 3, 2002 | Night | 7-0-0 | 7 | 7 |