The winning Connecticut Play3 numbers for December 3, 2000 were: night 0-0-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 3, 2000 | Night | 0-0-9 | 9 | 9 |
| Dec 2, 2000 | Night | 9-6-2 | 17 | 8 |
| Dec 1, 2000 | Night | 9-4-8 | 21 | 3 |
| Dec 1, 2000 | Day | 5-7-8 | 20 | 2 |
| Nov 30, 2000 | Night | 2-6-2 | 10 | 1 |
| Nov 30, 2000 | Day | 6-0-5 | 11 | 2 |
| Nov 29, 2000 | Night | 1-1-1 | 3 | 3 |
| Nov 29, 2000 | Day | 9-5-5 | 19 | 1 |
| Nov 28, 2000 | Night | 2-4-0 | 6 | 6 |
| Nov 28, 2000 | Day | 6-6-6 | 18 | 9 |
| Nov 27, 2000 | Night | 6-5-0 | 11 | 2 |
| Nov 27, 2000 | Day | 2-7-3 | 12 | 3 |