The winning Connecticut Play3 numbers for November 4, 2000 were: night 7-0-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 4, 2000 | Night | 7-0-5 | 12 | 3 |
| Nov 3, 2000 | Night | 0-2-4 | 6 | 6 |
| Nov 3, 2000 | Day | 5-2-9 | 16 | 7 |
| Nov 2, 2000 | Night | 8-1-0 | 9 | 9 |
| Nov 2, 2000 | Day | 8-1-7 | 16 | 7 |
| Nov 1, 2000 | Night | 8-1-9 | 18 | 9 |
| Nov 1, 2000 | Day | 7-9-7 | 23 | 5 |
| Oct 31, 2000 | Night | 6-6-9 | 21 | 3 |
| Oct 31, 2000 | Day | 1-2-4 | 7 | 7 |
| Oct 30, 2000 | Night | 8-9-3 | 20 | 2 |
| Oct 30, 2000 | Day | 0-6-1 | 7 | 7 |
| Oct 29, 2000 | Night | 7-4-0 | 11 | 2 |