The winning Connecticut Play3 numbers for October 11, 2000 were: day 7-0-9; night 7-6-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 11, 2000 | Night | 7-6-6 | 19 | 1 |
| Oct 11, 2000 | Day | 7-0-9 | 16 | 7 |
| Oct 10, 2000 | Night | 0-5-5 | 10 | 1 |
| Oct 10, 2000 | Day | 7-2-6 | 15 | 6 |
| Oct 9, 2000 | Night | 7-8-6 | 21 | 3 |
| Oct 9, 2000 | Day | 4-6-9 | 19 | 1 |
| Oct 8, 2000 | Night | 1-0-9 | 10 | 1 |
| Oct 7, 2000 | Night | 8-5-4 | 17 | 8 |
| Oct 6, 2000 | Night | 2-3-4 | 9 | 9 |
| Oct 6, 2000 | Day | 0-6-2 | 8 | 8 |
| Oct 5, 2000 | Night | 9-7-0 | 16 | 7 |
| Oct 5, 2000 | Day | 0-1-2 | 3 | 3 |