The winning Connecticut Play3 numbers for October 5, 2000 were: day 0-1-2; night 9-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 5, 2000 | Night | 9-7-0 | 16 | 7 |
| Oct 5, 2000 | Day | 0-1-2 | 3 | 3 |
| Oct 4, 2000 | Night | 9-9-3 | 21 | 3 |
| Oct 4, 2000 | Day | 8-3-9 | 20 | 2 |
| Oct 3, 2000 | Night | 9-6-4 | 19 | 1 |
| Oct 3, 2000 | Day | 2-4-2 | 8 | 8 |
| Oct 2, 2000 | Night | 2-7-1 | 10 | 1 |
| Oct 2, 2000 | Day | 1-1-7 | 9 | 9 |
| Oct 1, 2000 | Night | 0-0-8 | 8 | 8 |
| Sep 30, 2000 | Night | 1-0-3 | 4 | 4 |
| Sep 29, 2000 | Night | 0-0-7 | 7 | 7 |
| Sep 29, 2000 | Day | 6-0-9 | 15 | 6 |